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#2
tongzhipeng2012-05-03 23:44
我自己百度了一下，因为以前没见过cout.put()的用法
cout.put(ch)的用法 等同于cout << ch; 在你的代码里面ch在＋１后由M变成了Ｎ,这也就是你那个Ｎ产生的原因了，至于为什么在最前面我就不知道了，可能是cout.put()的功能是将字符插入到输出流的最前面。 cout.put(ch) man 了一下，应该是这段 template<typename _CharT , typename _Traits > basic_ostream< _CharT, _Traits > & std::basic_ostream< _CharT, _Traits >::put (char_type __c) Simple insertion. Parameters: c The character to insert. Returns: *this 我猜是 返回的是输出流对象的指针，也就是你后面打印的0047CE94 其实这段代码真正的逻辑应该还是这样写的  程序代码：#include <iostream> using namespace std; int main () { char ch = 'M'; int i = ch; cout << "The ASCⅡ code for " << ch << " is "<< i << endl; cout << "Add one to the character code;"<< endl; ch = ch + 1; i = ch; cout << "The ASCⅡ code for " << ch << " is " << i << endl; cout << " Displaying char ch using cout.put(ch): "; cout.put(ch) << endl; cout << " Done !" << endl; return 0; } [ 本帖最后由 tongzhipeng 于 2012-5-3 23:46 编辑 ] |
#include <iostream>
using namespace std;
int main ()
{
char ch = 'M';
int i = ch;
cout << "The ASCⅡ code for " << ch << " is "<< i << endl;
cout << "Add one to the character code;"<< endl;
ch = ch + 1;
i = ch;
cout << "The ASCⅡ code for " << ch << " is " << i << endl;
cout << " Displaying char ch using cout.put(ch): " << cout.put(ch) << endl;
cout << " Done !" << endl;
return 0;
}
为什么得出来是：
The ASCⅡ code for M is 77
Add one to the character code;
The ASCⅡ code for N is 78;
N Displaying char ch using cout.put(ch):0047CE94
Done!
不是应该这样吗？：
The ASCⅡ code for M is 77
Add one to the character code;
The ASCⅡ code for N is 78;
Displaying char ch using cout.put(ch):0047CE94
Done!
怎么在Displaying前面会出现一个“N”？？
[ 本帖最后由 Cai_xw1993 于 2012-5-3 22:00 编辑 ]
