求一份用c++编写的杨辉三角 - 编程论坛

#2

wtujoxk2012-03-26 19:47

程序代码：

#include <iostream>
using namespace std;

int main()
{
    const int num = 8;
    int i, j;
    int a[num][num];

    for (i=0; i<num; i++)
    {
        for (j=0; j<=i; j++)
        {
            if (j==0 || j==i)
            {
                a[i][j] = 1;
            }
            else
            {
                a[i][j] = a[i-1][j-1] + a[i-1][j];
            }
            cout<<a[i][j]<<"\t";
        }
        cout<<"\n\n";
    }

    return 0;
}

/*
输出结果为:
1

1       1

1       2       1

1       3       3       1

1       4       6       4       1

1       5       10      10      5       1

1       6       15      20      15      6       1

1       7       21      35      35      21      7       1

Press any key to continue
*/

#3

yubiaohyb2012-03-29 00:01

同学编程其实一点都不难的
我也是刚学的只要你认真去学很简单的

#4

蓝xuan2012-03-31 18:20

#include<iostream.h>
const int N=20;
void  fun(int *const c,int n)
{
    for(int i=0;i<=n;i++)
    {
        c[i]=1;
        for(int j=i-1;j>0;j--)
            c[j]=c[j-1]+c[j];
    }
}
void main()
{
    int n,*ptr,k=1;
    do
    {
        cout<<"输入二次项幕次方数:";
        cin>>n;
    }while(n<1||n>30);
    cout<<k<<endl;
    ptr=new int[n+1];
    while(k)
    {
        fun(ptr,k);
        for(int i=0;i<=k;i++)
            cout<<ptr[i]<<"  ";
        k++;
        if(k>n)
            break;
        cout<<endl;
    }
    delete []ptr;
    cout<<endl;
}

输入二次项幕次方数:8
1
1  1
1  2  1
1  3  3  1
1  4  6  4  1
1  5  10  10  5  1
1  6  15  20  15  6  1
1  7  21  35  35  21  7  1
1  8  28  56  70  56  28  8  1
Press any key to continue