关于命令行参数的问题，求秒杀！

#include<iostream>
#include<fstream>
#include<cstdlib>
using namespace std;
int main(int argc,char *argv[])
{
    int number[9]={11,22,33,44,55,66,77,88,99};
    if(argc!=3)
    {
        cout<<"argc="<<argc<<endl;
        cout<<"error in argument"<<endl;
        exit(1);
    }//应该是这里的问题吧，
    ofstream fout1,fout2;
    fout1.open(argv[1]);
    if(fout1.fail())
    {
        cout<<"could not open the file"<<argv[1]<<endl;
        exit(1);
    }
    fout2.open(argv[2]);
    if(fout2.fail())
    {
        cout<<"could not open the file"<<argv[2]<<endl;
        exit(1);
    }
    for(int i=0;i<9;i++)
    {
        if(number[i]%2==0)
            fout2<<number[i]<<" ";
        else
            fout1<<number[i]<<" ";
    }
    fout1.close();
    fout2.close();
    ifstream fin;
    char ch;
    for(int i=1;i<argc;i++)
    {
        fin.open(argv[i]);
        cout<<"contents of"<<argv[i]<<endl;
        do
        {
            fin.get(ch);
            cout<<ch;
        }
        while(fin);
        cout<<"\n\n";
        fin.close();
    }
    return 0;
}