这个要怎么实现啊？

#include<iostream>
#include <vector>
using namespace std;

// 代码比较重复，目前只支持二个字符查询，但三个条件基本上还是能满足！

int main(){

   
    char a[]="Hubei";
    char b[]="Heilongjiang";
    char c[]="Hebei";
    char d[]="Shanxi";
    char e[]="Shaanxi";
    int num = 0;   //标记是否含有c1[0]
   
    char c1[2];

    while (1) {
        cout<<"输入你要查询的词：";
        cin>>c1;
      
        for( int i=0;i<sizeof(a);i++){
            if (a[i]==c1[0]||a[i]-c1[0]==-32||a[i]-c1[0]==32) { //判断第一个字符，过滤大小写
               
                num = 1;
               
            }
            if (a[i]==c1[1]&&num==1||a[i]-c1[0]==-32||a[i]-c1[0]==32) { //判断第二个字符，过滤大小写
                cout<<a<<endl;
                num=0;
                break;
            }
           
      
        }
   
    for( i=0;i<sizeof(b);i++){
        if (b[i]==c1[0]||b[i]-c1[0]==-32||b[i]-c1[0]==32) {
           
            num = 1;
           
        }
        if (b[i]==c1[1]&&num==1||b[i]-c1[0]==-32||b[i]-c1[0]==32) {
            cout<<b<<endl;
            num=0;
            break;
           
    }}
    for( i=0;i<sizeof(c);i++){
        if (c[i]==c1[0]||c[i]-c1[0]==-32||c[i]-c1[0]==32) {
           
            num = 1;
           
        }
        if (c[i]==c1[1]&&num==1||c[i]-c1[0]==-32||c[i]-c1[0]==32) {
            cout<<c<<endl;
            break;
    }}
    for( i=0;i<sizeof(d);i++){
        if (d[i]==c1[0]||d[i]-c1[0]==-32||d[i]-c1[0]==32) {
           
            num = 1;
           
        }
        if (d[i]==c1[1]&&num==1||d[i]-c1[0]==-32||d[i]-c1[0]==32) {
            cout<<d<<endl;
            num=0;
            break;
    }}
    for( i=0;i<sizeof(d);i++){
        if (d[i]==c1[0]||d[i]-c1[0]==-32||d[i]-c1[0]==32) {
           
            num = 1;
           
        }
        if (d[i]==c1[1]&&num==1||d[i]-c1[0]==-32||d[i]-c1[0]==32) {
            cout<<d<<endl;
            num=0;
            break;
    }}
    for(i=0;i<sizeof(e);i++){
        if (e[i]==c1[0]||e[i]-c1[0]==-32||e[i]-c1[0]==32) {
           
            num = 1;
           
        }
        if (e[i]==c1[1]&&num==1||e[i]-c1[0]==-32||e[i]-c1[0]==32) {
            cout<<e<<endl;
            num=0;
            break;
    }}
   


    }   
      
}