两个4X4矩阵相乘，得到另一个矩阵，并将其输出，我这错了，可是不会改 - 编程论坛

#2

wube2011-06-07 19:52

上面的结果长这样～.NET不熟矩阵忘了～帮不了你～

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#3

qq10235692232011-06-07 20:00

程序代码：

  For i = 1 To 4
  For j = 1 To 4
  For k=1 To 4 '相乘的时候错了
  c(i, j) = c(i, j) + a(i, k) * b(k, j)
  Print c(i, j);
  Next k
  Next j
  Print
  Next i
  End Sub

#4

sywzs2011-06-09 04:52

把 1 To 4 改成 0 to 3 试试。

#5

dragen1112011-06-09 12:43

Private Sub Form_Click()
Dim a(4, 4) As Integer, b(4, 4) As Integer, c(4, 4) As Integer, i%, j%
Print "A矩阵为"
For i = 1 To 4
  For j = 1 To 4
   a(i, j) = Int(Rnd * 30) + 10

   Print a(i, j);
   Next j
   Print
   Next i
   Print


  Print "B矩阵为"
  For i = 1 To 4
  For j = 1 To 4

    b(i, j) = Int(Rnd * 30) + 10
   Print b(i, j);
   Next j
   Print
   Next i
   Print


   Print "C矩阵为"
For i = 1 To 4
  For j = 1 To 4
  c(i, j) = a(i, j) * b(i, j)
  Print c(i, j);
  Next j
  Print
  Next i
End Sub

#6

lianjiecuowu2011-06-12 09:26

#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
{
    int i,j,t;
    const int M=2;
    const int N=3;
    const int K=4;
    int m[M][K];
    int n[K][N];
    int k[M][N]={0};
    srand(time(NULL));
    for(i=0;i<M;i++)
    {
        for(t=0;t<K;t++)
            m[i][t]=rand()%100;
    }
    cout<<"请输出数组m的元素："<<endl;
    for(i=0;i<M;i++)
    {
        for(t=0;t<K;t++)
            cout<<m[i][t]<<"\t";
        cout<<endl;
    }
    for(t=0;t<K;t++)
    {
        for(j=0;j<N;j++)
            n[t][j]=rand()%100;
    }
    cout<<"输出数组n的元素："<<endl;
    for(t=0;t<K;t++)
    {
        for(j=0;j<N;j++)
            cout<<n[t][j]<<"\t";
        cout<<endl;
    }



    for(i=0;i<M;i++)
        for(j=0;j<N;j++)
            for(t=0;t<K;t++)
                k[i][j]=k[i][j]+m[i][t]*n[t][j];
            cout<<"输出乘积后k数组的元素："<<endl;
            for(i=0;i<M;i++)
            {
                for(j=0;j<N;j++)
                    cout<<k[i][j]<<"\t";
                cout<<endl;
            }
    system("pause");
    return 0;

}