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请教关于CString

MQKt 发布于 2011-05-18 08:40, 424 次点击
在LIST BOX控件中读到一行文字,文字规律是 “文字+两个空格+文字+两个空格+文字+两个空格+数值”
请教如何得到这个数值?
5 回复
#2
yuccn2011-05-18 09:08
查下MSDN中的CString,里面的成员函数应该能满足你的要求的,

[ 本帖最后由 yuccn 于 2011-5-18 09:25 编辑 ]
#3
MQKt2011-05-18 09:11
就是没MSDN咯,记得的只有一个find,right,left,GetLength
#4
yuccn2011-05-18 09:25
能上网也行了啊,到微软官方的MSDN去查就行了
#5
yuccn2011-05-18 09:29
CString::Format
void Format( LPCTSTR lpszFormat, ... );

void Format( UINT nFormatID, ... );

Parameters

lpszFormat

A format-control string.

nFormatID

The string resource identifier that contains the format-control string.

Remarks

Call this member function to write formatted data to a CString in the same way that sprintf formats data into a C-style character array. This function formats and stores a series of characters and values in the CString. Each optional argument (if any) is converted and output according to the corresponding format specification in lpszFormat or from the string resource identified by nFormatID.

The call will fail if the string object itself is offered as a parameter to Format. For example, the following code:

CString str = "Some Data";
str.Format("%s%d", str, 123);   // Attention: str is also used in the parameter list.

will cause unpredictable results.

When you pass a character string as an optional argument, you must cast it explicitly as LPCTSTR. The format has the same form and function as the format argument for the printf function. (For a description of the format and arguments, seeprintf in the Run-Time Library Reference.) A null character is appended to the end of the characters written.

For more information, seesprintf in the Run-Time Library Reference.

Example

CString str;

str.Format(_T("Floating point: %.2f\n"), 12345.12345);
_tprintf("%s", (LPCTSTR) str);

str.Format(_T("Left-justified integer: %.6d\n"), 35);
_tprintf("%s", (LPCTSTR) str);

str.Format(IDS_SCORE, 5, 3);
_tprintf("%s", (LPCTSTR) str);
   

Output

If the application has a string resource with the identifier IDS_SCORE that contains the string "Penguins: %d\nFlyers  : %d\n", the above code fragment produces this output:

Floating point: 12345.12
Left-justified integer: 000035
Penguins: 5
Flyers  : 3

msdn上烤过来的
#6
MQKt2011-05-18 09:39
下载了一个,谢谢
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