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#2
糖包包2011-03-31 14:44
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题目是已知一函数y=x(x<1)
=2x-1(1<=x<10)
=3x-11(x>=10)
输入x的值,输出y的值。
#include <iostream.h>
void main()
{
double x,y;
cout<<"input x:";
cin>>x;
if(x<1) y=x;
else if(1<=x<10)
y=2x-1;
else
y=3x-11;
cout<<"y="<<y<<endl;
}