编程学习例二 - 编程论坛

#2

li_danwang2010-12-14 08:15

经典...

#3

missiyou2010-12-14 10:49

#include<iostream>

using namespace std;
bool LogMsg(string str)
{
    if (str.empty())
        return false;
    cout << str.c_str() << endl;
    return true;
}

bool LogMsgLastLine(string str)
{
   return  LogMsg(str);
}

int main(int argc, char* argv[])
{
    string str;
    str.append("For he's a jolly good fellow!\n");
    str.append(str);
    str.append(str);
    str.erase((str.length() - 1));
    LogMsg(str);
    LogMsgLastLine("Which noboby can deny!\n");
    return 0;

}

#4

jm76451782011-01-24 13:21

回复 2楼 li_danwang

#5

Amy_huyier2011-01-25 16:02

这题。有点无语啊

#6

慢慢的走着2011-01-25 16:56

我選擇用內聯函數了...

#7

popo52525212012-02-12 22:02

#include <stdio.h>
void prinF(void);    \*函数声明*\
void prinW(void);    \*函数声明*\
int main(void)
{
prinF();            \*函数调用*\
prinF();            \*函数调用*\
prinF();            \*函数调用*\
prinW();            \*函数调用*\
return 0;
}

void prinF()         \*函数定义*\
{
printf("For he's a jolly good fellow!\n");
}

void prinW()         \*函数定义*\
{
printf("Which noboby can deny!\n");
}

运行错误啊

#8

popo52525212012-02-12 22:05

回三楼是不是复杂化了？

#9

popo52525212012-02-12 22:30

#include "stdio.h"
void main()
{
    int i = 0;
    for(i = 0; i<3; i++)
    printf("For he's a jolly good fellow!\n");
    printf("Which nobody can deny!\n");
}