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怎么双行输出

诺亚Kiss 发布于 2010-09-07 15:05, 384 次点击
这个程序:
#ifndef _TM_DEFINED
struct tm
{
     int tm_sec;     
     int tm_min;   
     int tm_hour;   
     int tm_mday;   
     int tm_mon;     
     int tm_year;   
    int tm_wday;   
int tm_yday;   
     int tm_isdst;  
 };
#define _TM_DEFINED
#endif

#include <iostream.h>
#include <time.h>
int main(void)
{
        struct tm *local;
        long t;
        time(&t);
        cout << "The Calendar Time now is:" << t << endl ;
        local = localtime(&t);
        local->tm_year = local->tm_year + 1900;
        local->tm_mon ++;
        cout << "今天是: " << local->tm_year    << "年" << local->tm_mon
            << "月" << local->tm_mday << "日" << "星期" << local->tm_wday
            <<"当前的时间是:"<< local->tm_hour
            << "时" << local->tm_min  << "分" << local->tm_sec <<"秒"
             << endl;
        return 0;
}
怎么才能像这样输出:
今天是: 2005年12月20日,星期二
当前时间是:22时40分43秒
应该怎么办?怎么改啊?
3 回复
#2
蛤蟆VS天鹅2010-09-07 15:20

<< "月" << local->tm_mday << "日" << "星期" << local->tm_wday
            <<"当前的时间是:"<< local->tm_hour
改为

 << "月" << local->tm_mday << "日" << "星期" << local->tm_wday<<endl;
        cout <<"当前的时间是:"<< local->tm_hour

就ok了
#3
l3763653332010-09-07 18:28
请问time(&t);还有这个t是什么意思
#4
amwjgigql2010-09-07 23:04
将这一句cout << "今天是: " << local->tm_year    << "年" << local->tm_mon
            << "月" << local->tm_mday << "日" << "星期" << local->tm_wday
            <<"当前的时间是:"<< local->tm_hour
            << "时" << local->tm_min  << "分" << local->tm_sec <<"秒"
             << endl;
改为二句
cout << "今天是: " << local->tm_year    << "年" << local->tm_mon
            << "月" << local->tm_mday << "日" << "星期" << local->tm_wday<<ednl;
cout <<"当前的时间是:"<< local->tm_hour
            << "时" << local->tm_min  << "分" << local->tm_sec <<"秒"
             << endl;
1