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求一个简单的算法,急,先谢了

lc1234 发布于 2010-06-08 21:00, 547 次点击
输入一个参数,燃火打印出相应的维数,例:输入4 输出
 0000
 0111
 0122
 0123
2 回复
#2
linjx01232010-06-09 10:47
程序代码:
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        while(n<=0){
            System.out.println("n must greater than zero, please input a number again");
            n = in.nextInt();
        }
        int a[][] = new int[n][n];
        for(int i = 0; i<n;i++){
            for(int j=0;j<n;j++){
                if(j>=i)
                    a[i][j]=i;
                else
                    a[i][j]=j;
                System.out.print(a[i][j]+" ");
            }
            System.out.println();
        }   
    }
}
#3
lc12342010-06-22 21:38

    for(int i=0;i<4;i++)
    {
        for(int j=0;j<4;j++)
        System.out.print(j>i?i:j);
        System.out.println();
    }

这个是不是更精辟一些呢
1