析构函数带来的错误

各位高手，我的程序如下，如果没有析构函数(红色文字)就能正常运行，如果加上析构函数，就不能正常运行。请问为什么？如果要用析构函数的话，应该怎么写代码。谢谢!
#include<iostream.h>
#include<string.h>

class Person
{
private:
    char* name;
    int age;
    char* gender;
public:
    Person(){}
    Person(const char *name_t,const int age_t,const char *gender_t);
    Person(Person& person);
    void setName(const char *name_t);
    void setAge(const int age_t);
    void setGender(const char *gender_t);
    char* getName();
    int getAge();
    char* getGender();
    void display();
    ~Person()
    {
        delete[] name;
        delete[] gender;
    }
};
Person :: Person(const char *name_t,const int age_t,const char *gender_t)
{
    name = new char[strlen(name_t) + 1];
    strcpy(name,name_t);
    gender = new char[strlen(gender_t) + 1];
    strcpy(gender,gender_t);
    age = age_t;
}
Person :: Person(Person& person)
{
    name = new char[strlen(person.name) + 1];
    strcpy(name,person.name);
    gender = new char[strlen(person.gender) + 1];
    strcpy(gender,person.gender);
    age = person.age;   
}

void Person::setName(const char* name_t)
{
    name = new char[strlen(name_t) + 1];
    strcpy(name,name_t);
}
void Person ::setAge(const age_t)
{
    age = age_t;
}
void Person :: setGender(const char* gender_t)
{
    gender = new char[strlen(gender_t) + 1];
    strcpy(gender,gender_t);
}
char* Person :: getName()
{
    return name;
}
int Person :: getAge()
{
    return age;
}
char* Person :: getGender()
{
    return gender;
}
void Person :: display()
{
    cout << name << " | " << age << " | " << gender << endl;
}

//建立类模板Relation,该类模板生成的模板类由参数K、T决定。
template <class K,class T>
class Relation
{
private:
    K key;
    T value;
public:
    Relation(){}
    Relation(const K& k,const T& v)
    {
        key = k;
        value = v;
    }
    K getKey()
    {
        return key;
    }
    T getValue()
    {
        return value;
    }
    void setKey(const K& k)
    {
        key = k;
    }
    void setValue(const T& v)
    {
        value = v;
    }
};
//在主函数中测试
int main()
{
    Relation<char* ,Person> r;
    r.setKey("CEO");
    Person person("张三",40,"男");
    r.setValue(person);
    cout << r.getKey() <<" : ";
    r.getValue().display();
    return 0;
}