怎么传递查询出的值？

我才学PHP，在自己编的一个网页里，想在点击了“Alter”按钮以后把该行查询出的$row['address']传到另外一个页面中（alter.php）。
哪位高手帮忙想想怎么弄啊，谢谢了~~

  $array[50];
  $i = 0;
  while($row = mysql_fetch_array($result)){
    echo "<tr>";
    echo "<td align = 'center'>" . $row['id_z'] . "</td>";
    echo "<td align = 'center'>" . $row['name_z'] . "</td>";
    echo "<td align = 'center'>" . $row['address'] . "</td>";
    echo "<td align = 'center'>" . $row['type_w'] . "</td>";
    echo "<td align = 'center'>" . $row['id_s'] . "</td>";  
    echo "<td align = 'center'>" . $row['time_sq'] . "</td>";
    echo "<td align = 'center'>" . $row['time_sh'] . "</td>";
    echo "<td align = 'center'>" . $row['result'] . "</td>";
    echo "<td align = 'center'><input type = 'submit' size = '15' name ='" . $array[$i] . "'
              value = 'Alter' ></td>";
    echo "</tr>";
    $i++;
  }