新手想问问问题出在哪了 - 编程论坛

#2

haoliliang882010-03-17 10:02

#include<stdio.h>
#include<file2.h>
struct month
{int number;
char english_name;
int days;
}mon[12];
enum english_month{January,February,Marcy,April,May,June,July,August,September,October,November,December};
enum month_englishname;
month_englishname=Februar
void main()
{int i;
for(i=1;i<=12;i++)
{mon[i-1].number=i;
switch(month_englishname)
{case January:mon[i-1].english_name=January;
break;
case February:mon[i-1].english_name=February;
break;
case Marcy:mon[i-1].english_name=Marcy;
break;
case April:mon[i-1].english_name=April;
break;
case May:mon[i-1].english_name=May;
break;
case June:mon[i-1].english_name=June;
break;
case July:mon[i-1].english_name=July;
break;
case August:mon[i-1].english_name=August;
break;
case September:mon[i-1].english_name=September;
break;
case October:mon[i-1].english_name=October;
break;
case November:mon[i-1].english_name=November ;
break;
case December:mon[i-1].english_name=December;
break;
}
month_englishname++;
if(i%2==0)
mon[i-1].days=31;
else mon[i-1].days=30;
mon[1].days=28or29;
printf("月份英语名天数\n");
printf("%d\t\t%s\t\t%s\n",mon[i-1].number,mon[i-1].english_name,mon[i-1].days);}}
请问大家这个程序问题出在哪了？

#3

hahayezhe2010-03-17 10:19

搞这么长还不给分

#4

mghxz2522010-03-17 15:51

我改了一下，能运行出来，但不能显示月份的英文名，楼主再改一下，完了的发记得发出来。

程序代码：

#include <stdio.h>
struct month
{int number;
char english_name;
int days;
}mon[12];
enum english_month{January,February,Marcy,April,May,June,July,August,September,October,November,December};
int main(void)
{int i;
for(i=1;i<=12;i++)
{char month_englishname;
switch(month_englishname)
{
case January:mon[i-1].english_name=January;
break;
case February:mon[i-1].english_name=February;
break;
case Marcy:mon[i-1].english_name=Marcy;
break;
case April:mon[i-1].english_name=April;
break;
case May:mon[i-1].english_name=May;
break;
case June:mon[i-1].english_name=June;
break;
case July:mon[i-1].english_name=July;
break;
case August:mon[i-1].english_name=August;
break;
case September:mon[i-1].english_name=September;
break;
case October:mon[i-1].english_name=October;
break;
case November:mon[i-1].english_name=November ;
break;
case December:mon[i-1].english_name=December;
break;
}
month_englishname++;
if(i%2==0)
mon[i-1].days=31;
else mon[i-1].days=30;
printf("月份英语名天数\n");
printf("%d\t\t%d\t\t%d\n",i,mon[i-1].english_name,mon[i-1].days);
}
return 0;
}

#5

apull2010-03-17 17:44

回复楼主 haoliliang88

程序代码：

#include <stdio.h>
#include <string.h>

struct month
{
    int number;
    char english_name[15];
    int days;
} mon[12];

int days[12]={31,28,31,30,31,30,31,31,30,31,30,31};
char enName[12][15]={"January","February","Marcy","April","May","June","July","August","September","October","November","December",};

int main(void)
{
    int i;
    printf(" 月份\t 天数\t 英语名  \n");
    for(i=0; i<12; i++)
    {
        mon[i].number=i+1;
        strcpy(mon[i].english_name,enName[i]);
        mon[i].days=days[i];
        printf("%4d\t%4d\t%s\n",mon[i].number,mon[i].days,mon[i].english_name);
    }
    return 0;
}

enum 虽然是英文名字，但是真实的值是从0开始计算的。因此不能用于显示月份名。
既然mon的number存储了月份，那就直接输出，没必要用i。

#6

haoliliang882010-03-17 17:56

#include <stdio.h>
struct month
{int number;
char english_name;
int days;
}mon[12];
enum english_month{J,F,M,A,K,J,G,H,S,O,N,D};
enum english_month month_englishname;
int main(void)
{int i;
for(i=1;i<=12;i++)
{mon[i-1].number=i;
char month_englishname;
month_englishname=1;
switch(month_englishname)
{
case J:mon[i-1].english_name="January";
break;
case F:mon[i-1].english_name="February";
break;
case M:mon[i-1].english_name="Marcy";
break;
case A:mon[i-1].english_name="April";
break;
case K:mon[i-1].english_name="May";
break;
case J:mon[i-1].english_name="June";
break;
case G:mon[i-1].english_name="July";
break;
case H:mon[i-1].english_name="August";
case S:mon[i-1].english_name="September";
case O:mon[i-1].english_name="October";
break;
case N:mon[i-1].english_name="November";
break;
case D:mon[i-1].english_name="December";
break;
}
month_englishname++;
if(i%2==0)
mon[i-1].days=30;
else mon[i-1].days=31;
printf("月份英语名天数\n");
printf("%d\t%s\t%d\n",mon[i-1].number,mon[i-1].english_name,mon[i-1].days);
}
return 0;
}
我又改了一下，可是还是有同一个错误，你再看看是怎么回事！

#7

幻or2010-03-17 23:15

顶下、、、

#8

haoliliang882010-03-17 23:55

狠人啊，顶啊，顶啊

#9

mghxz2522010-03-18 08:56

5楼的强悍啊，