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#2
xufen3402009-08-13 21:42
#include<iostream>
using namespace std; const int max=100; typedef struct{ char upnum[max]; char downnum[max]; int upnumlength; int downnumlength; } fraction; fraction getnum(char* parray); fraction getresult(fraction f1,fraction f2); int main() { char num1[max]; char num2[max]; cin>>num1>>num2; fraction mynum1=getnum(num1); fraction mynum2=getnum(num2); fraction result=getresult(mynum1,mynum2); int i; for(i=0;i<result.upnumlength;i++) cout<<result.upnum[i]; cout<<"/"; for(i=0;i<result.downnumlength;i++) cout<<result.downnum[i]; int y; cin>>y; } //返回分子分母 fraction getnum(char* parray) { fraction mynum; mynum.downnumlength=0; mynum.upnumlength=0; int i=0; int numlength=strlen(parray); while(parray[i]!='/'){ mynum.upnum[i]=parray[i];//取分子 i++; mynum.upnumlength++; } mynum.upnum[i]='\0'; int j=0; i++; while(i<numlength){ mynum.downnum[j]=parray[i];//取分母 i++; j++; mynum.downnumlength++; } mynum.downnum[j]='\0'; return mynum; } //分母加法换算 fraction getresult(fraction f1,fraction f2) { int upnum1,upnum2; int downnum1,downnum2; int downnum,upnum; fraction result; upnum1=atoi(f1.upnum); downnum1=atoi(f1.downnum); upnum2=atoi(f2.upnum); downnum2=atoi(f2.downnum); if(downnum1%downnum2==0){ downnum=downnum1; upnum=upnum1+upnum2; }else if(downnum2%downnum1==0){ downnum=downnum2; upnum=upnum1+upnum2; }else {//这里有个求最大公倍数先空着，一时想不出 downnum=downnum2*downnum1; upnum=upnum1*downnum2+upnum2*downnum1; } itoa(downnum,result.downnum,10); itoa(upnum,result.upnum,10); result.downnumlength=strlen(result.downnum); result.upnumlength=strlen(result.upnum); return result; } |
编写一程序计算两个整分数的和。程序运行结果应具有如下所示的形式：
输入第一个分数：1/2
输入第一个分数:2/5
两分数和为：9/10
（提示：输入分数时，可采用提示符链接形式，如输入a/b：cin>>a>dummy>>b;）
来人帮忙编个哈，在这先谢谢了。还有我主要是那个提示不懂。不知道是什么意思。
