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#2
zhangyafei43532008-11-30 20:26
改至别人的程序,仅供参考
你看看有用没:
#include<iostream.h> #include<math.h> class Date { public: Date()// { year=0000; month=00; day=00; } Date(int year_input,int month_input,int day_input)// { year=year_input; month=month_input; day=day_input; } void date_set(int year_input,int month_input,int day_input)// { year=year_input; month=month_input; day=day_input; } void date_output() { cout<<year<<"--"<<month<<"--"<<day<<endl; } void date_plus() { if(day+1<=get_days(month,year)) day++; else { month_plus(); day=1; } } void date_down() { if(day-1>=1) day--; else { month_down(); day=get_days(month,year); } } void month_plus() { if(month+1<=12) month++; else { year++; month=1; } } void month_down() { if(month-1>=1) month--; else { year--; month=12; } } int days_calculate(int year_input,int month_input,int day_input)//计算两个日期间的天数 { int total_days=0; int leapyears; int i; if(year_input==year) { for(i=1;i<month;i++) total_days+=get_days(i,year); total_days+=day; for(i=1;i<month_input;i++) total_days-=get_days(i,year_input); total_days-=day_input; return abs(total_days); } else if(year_input<year) { leapyears=0; for(i=year_input;i<year;i++) if(is_leap(i)) leapyears++; total_days=(year-year_input)*365+leapyears; for(i=1;i<month;i++) total_days+=get_days(i,year); total_days+=day; for(i=1;i<month_input;i++) total_days-=get_days(i,year_input); total_days-=day_input; return abs(total_days); } else { leapyears=0; for(i=year;i<year_input;i++) if(is_leap(i)) leapyears++; total_days=(year_input-year)*365+leapyears; for(i=1;i<month_input;i++) total_days+=get_days(i,year_input); total_days+=day_input; for(i=1;i<month;i++) total_days-=get_days(i,year); total_days-=day; return abs(total_days); } } private: int get_days(int month_,int year_) { switch(month_) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: return 31; break; case 4: case 6: case 9: case 11: return 30; break; case 2: if(is_leap(year_)) return 29; else return 28; break; default: return 0; } } bool is_leap(int year_) { if(year_%4) return false; else if(year_%100) return true; else if(year_%400) return false; return true; } private: int year,month,day; }; void main() { int m_year,m_month,m_Day,result; char m_choice; Date date(2008,11,26); cout<<" 1.日期的设置'S';2.日期的显示'X';3.日期加一天'A';\n 4.日期减一天'J';5.日期算间隔'G';6.退出'Q';\n\n\n"<<endl; while(m_choice!='Q') { cout<<"请选择:"; cin>>m_choice; switch(m_choice) { case 'S': cout<<"Y:"; cin>>m_year; cout<<"M:"; cin>>m_month; cout<<"D:"; cin>>m_Day; date.date_set(m_year,m_month,m_Day); break; case 'X': break; case 'A': date.date_plus(); break; case 'J': date.date_down(); break; case 'G': cout<<" 目前时间:\n\n"<<endl; date.date_output(); cout<<"Y:"; cin>>m_year; cout<<"M:"; cin>>m_month; cout<<"D:"; cin>>m_Day; result=date.days_calculate(m_year,m_month,m_Day); cout<<" 间隔时间:"<<result<<endl; break; } if(m_choice!='G') date.date_output(); } } |
有哪位学长能告诉我C++如何让program A link去program B.
Example:
[1]: Encrytion Module
[2]: Decrytion Module
[3]: Exit the Program
Your Choice: (如果我选择1,然后link去Encryption Module, 以此推类)
谢谢大家鼎立相救~P/S:能否告知了coding source后,在向我解释~