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#2
战士2008-07-01 19:55
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编一个求x的n次方的函数
#include <iostream.h>
double cf(double x,int n)
{
double b=1;
for(int a=1;a<=n;a++)
{
b*=a;
return b;
}
}
void main()
{
double x;int n;
cout<<"请输入X和N的值"<<endl;
cin>>x>>n;
cout<<x<<"的"<<n<<"次方为:"<<cf(x,n)<<endl;
}