运算符重载时出现问题了

zerocn 发布于 2008-06-25 17:46， 1797 次点击

#include <iostream>

using namespace std;

class Complex
{private:
float r,i;
public:
Complex operator + (Complex &b);
Complex();
Complex(float &,float &);
void show();
};

Complex Complex::operator +(Complex &b)
{Complex temp;
temp.r=r+b.r;
temp.i=i+b.i;
return (temp);
}

Complex::Complex()
{r=0;i=0;}
Complex::Complex(float &a, float &b)
{r=a;i=b;}
void Complex::show()
{if(r<0)cout<<r<<"-"<<i<<"i"<<endl;
else if(r=0)cout<<r<<endl;
else cout<<r<<"+"<<i<<endl;
               }

int main()
{ Complex c1(10,11),c2(12,13),c3;//编译时这里出错了
  c3=c1+c2;
  c3.show();
  return 0;
}

这里是报错的消息

no matching function for call to `Complex::Complex(int, int)'
Complex::Complex(float&, float&)
Complex::Complex()

我想是不是创建对象是把"10"看成int形，那么我改为"10F"这样还是不行

10 回复

zjl1382008-06-25 18:16

Complex(float &,float &);此函数改声明为Complex(float ,float );

定义那里也改一下.

hp521_kylin2008-06-25 21:51

我编译了一下：问题是你说的那个。
但是你有没有看明白：不能把const int 转换为float 还有2楼这位仁兄说的引用问题..

mqh213642008-06-26 16:44

那你就写成10.0这样不就好了啊！

guipengee2008-06-26 19:26

编译器使所有的临时对象自动成为const，你的参数按引用传递，就意味着它取临时对象的地址，就有可能修改临时对象。在参数里加上const就OK。

漫游者李李西2008-06-26 22:18

常数认为是const，可以在申明时加上const，要不在创建对象时传入名字代替10.

kongwei2542008-06-27 21:56

#include <iostream.h>

//using namespace std;

class Complex
{private:
float r,i;
public:
Complex operator + (Complex &b);
Complex();
Complex(float ,float );
void show();
};

Complex Complex::operator +(Complex &b)
{Complex temp;
temp.r=r+b.r;
temp.i=i+b.i;
return (temp);
}

Complex::Complex()
{r=0;i=0;}
Complex::Complex(float a, float b)
{r=a;i=b;}
void Complex::show()
{
    if(r<0)cout<<r<<"-"<<i<<"i"<<endl;
    else if(r=0)cout<<r<<endl;
    else cout<<r<<"+"<<i<<endl;
}

int main()
{ Complex c1(10,11),c2(12,13),c3;
  c3=c1+c2;
  c3.show();
  return 0;
}

可以了

雪城白鸟2008-06-28 16:22

我的答案

#include <iostream>
using namespace std;

class Complex
{
private:
        float RE_P;//real part
        float IM_P;//imaginary part
public:
        Complex operator + (const Complex &b);
        Complex(){RE_P=0; IM_P=0; }
        Complex(float a,float b ){RE_P=a; IM_P=b; }
        void show()const;
};

Complex Complex::operator +(const Complex &b)
{
    Complex temp;
    temp.RE_P=RE_P+b.RE_P;
    temp.IM_P=IM_P+b.IM_P;
    return temp;
}

void Complex::show()const
{
    if(IM_P==0)
      cout<<RE_P<<endl;
    else if(IM_P<0)
      cout<<RE_P<<IM_P<<"i\n";
    else
      cout<<RE_P<<"+"<<IM_P<<"i\n";
}

int main()
{ Complex c1(10,11),c2(12,13),c3;
  c3=c1+c2;
  c3.show();
  return 0;
}

雪城白鸟2008-06-28 16:23

kongwei254的不对

你的输出有问题，希望检查下

#10

byd9132008-07-04 14:19

改一下就可以了

#include <iostream>

using namespace std;

class Complex
{private:
float r,i;
public:
Complex operator + (Complex &b);
Complex();
Complex(float ,float );
void show();
};

Complex Complex::operator +(Complex &b)
{Complex temp;
temp.r=r+b.r;
temp.i=i+b.i;
return (temp);
}

Complex::Complex()
{r=0;i=0;}
Complex::Complex(float a, float b)
{r=a;i=b;}
void Complex::show()
{if(r<0)cout<<r<<"-"<<i<<"i"<<endl;
else if(r=0)cout<<r<<endl;
else cout<<r<<"+"<<i<<endl;
               }

int main()
{ Complex c1(10,11),c2(12,13),c3;//编译时这里出错了
  c3=c1+c2;
  c3.show();
  return 0;
}

#11

guoqingchun2008-07-08 15:13

我感觉我这个比较正确，呵呵

#include <iostream>
using namespace std;

class Complex{
private:
    float r,i;
public:
    Complex operator +(Complex &b);
    Complex();
    Complex(float,float);
    void show();
};

Complex Complex::operator +(Complex &b){
    Complex temp;
    temp.r=r+b.r;
    temp.i=i+b.i;
    return temp;
}

Complex::Complex(){r=0;i=0;}
Complex::Complex(float a, float b){
    r=a;i=b;
}
void Complex::show(){
    if(i<0)
        cout<<r<<"-"<<-i<<endl;
    else
        cout<<r<<"+"<<i<<endl;
}

int main(){
    Complex c1(10,11),c2(12,-13),c3;//编译时这里出错了
    c3=c1+c2;
    c3.show();
    return 0;
}