[求助]循环结构程序设计

“输入一行字符” 不解，还是统计个数不解呢？

[CODE][/CODE]
string str ;
cout << "please type in the string" << endl ;
cin >> str ;
// define three counter for number, letter(upper,lower), other characters , separately.
int num = 0 ;
int letter = 0 ;
int otherChar = 0 ;
for(string::iterator iter = str.begin() ; iter != str.end() ; ++iter)
{
if ( (*iter == '0')
||(*iter == '1')
||(*iter == '2')
||(*iter == '3')
||(*iter == '4')
||(*iter == '5')
||(*iter == '6')
||(*iter == '7')
||(*iter == '8')
||(*iter == '9')
)
{
++num;
}
else if( (*iter == 'a')
||(*iter == 'A')
||(*iter == 'b')
||(*iter == 'B')
||(*iter == 'c')
||(*iter == 'C')
||(*iter == 'd')
||(*iter == 'D')
||(*iter == 'e')
||(*iter == 'E')
||(*iter == 'f')
||(*iter == 'F')
||(*iter == 'g')
||(*iter == 'G')
||(*iter == 'h')
||(*iter == 'H')
||(*iter == 'i')
||(*iter == 'I')
||(*iter == 'j')
||(*iter == 'J')
||(*iter == 'k')
||(*iter == 'K')
||(*iter == 'l')
||(*iter == 'L')
||(*iter == 'm')
||(*iter == 'M')
||(*iter == 'n')
||(*iter == 'N')
||(*iter == 'o')
||(*iter == 'O')
||(*iter == 'p')
||(*iter == 'P')
||(*iter == 'q')
||(*iter == 'Q')
||(*iter == 'r')
||(*iter == 'R')
||(*iter == 's')
||(*iter == 'S')
||(*iter == 't')
||(*iter == 'T')
||(*iter == 'u')
||(*iter == 'U')
||(*iter == 'v')
||(*iter == 'V')
||(*iter == 'w')
||(*iter == 'W')
||(*iter == 'x')
||(*iter == 'X')
||(*iter == 'y')
||(*iter == 'Y')
||(*iter == 'z')
||(*iter == 'Z'))
{
++letter ;
}
else
{
++otherChar ;
}
}
cout << "there is " << num << " numbers, " << letter << " letters, " << otherChar
<< " other characters. " << endl ;

应该是这样.

isdigit()
isalpha()....之类的函数就可以了,自己找下~

LZ的题目有歧意。

7楼的方法很好，不过i貌似没有自增。。。，另外lz请说出不解的地方。

修改了一下：
#include<stdio.h>
void main()
{
int alpha=0, digit=0, other=0;
char str[256];
gets(str);
int i=0;
while(str[i])
{
if((str[i]>='a'&&str[i]<='z')||(str[i]>='A'&&str[i]<='Z'))
++alpha;
else
if(str[i]>='0'&&str[i]<='9')
++digit;
else
++other;
i++;
}
printf("%d\n%d\n%d\n",alpha,digit,other);
}

[此贴子已经被作者于2007-10-2 19:53:31编辑过]

#include<iostream.h>
#include<string.h>
int main()
{
char* a=new char[50];
int i,m,sum1=0,sum2=0,sum3=0;
cout<<"please enter!"<<endl;
cin>>a;
m=strlen(a);
for(i=0;i<m;i++)
{
if(a[i]>=48&&a[i]<=59)
sum1++;
if(a[i]>=65&&a[i]<=90)
sum2++;
if(a[i]>=97&&a[i]<=122)
sum3++;
}
cout<<"数字共有"<<sum1<<"个"<<endl;
cout<<"大写字母共有"<<sum2<<"个"<<endl;
cout<<"小写字母共有"<<sum3<<"个"<<endl;
return 0;
}

4楼的代码。。。。。
瀑布汗啊。。。

修改了一下：
#include<iostream.h>
#include<string.h>
void main()
{
int alpha=0, digit=0, other=0;
char str[256];
char *s=str;
cin.getline(s,256,'\0');
int i=0;
while(str[i]!='\0')
{
if((str[i]>='a'&&str[i]<='z')||(str[i]>='A'&&str[i]<='Z'))
++alpha;
else
if(str[i]>='0'&&str[i]<='9')
++digit;
other=sizeof(s)-alpha-digit;
i++;
}
cout<<alpha<<"\n"<<digit<<"\n"<<other<<endl;
}