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这个会话为什么出不来结果呢?

大嘴先生2 发布于 2007-09-18 11:11， 1258 次点击

import java.io.IOException;


import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;

public class SessionInfo1 extends javax.servlet.http.HttpServlet implements javax.servlet.Servlet {
static final long serialVersionUID = 1L;

public SessionInfo1() {
super();
}


protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html,charset=GBK");
String user = request.getParameter("uesr");
HttpSession session = request.getSession();
if(user.length()>0)
{
session.setAttribute("user", user);
}
RequestDispatcher rd = request.getRequestDispatcher("display");
rd.forward(request, response);
}





protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doGet(request,response);
}
}
//代码2

import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
public class Display extends javax.servlet.http.HttpServlet implements javax.servlet.Servlet {
static final long serialVersionUID = 1L;
public Display() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("test/html;charset=GBK");
HttpSession session = request.getSession();
String user = (String)session.getAttribute("user");
if(user!=null)
{
response.getWriter().println("欢迎你"+user);
}
else
{
response.getWriter().println("请登陆");
}
}

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doGet(request,response);
}
}
//代码3
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=GBK">
<title>Login</title>
</head>
<body>
<form Action="Login" method="post">
用户名:<input type="text" name="user">
密码: <input type="password" name="password">
<input type="submit">
</form>
</body>
</html>

//帮忙看看,谢谢拉

13 回复
#2
大嘴先生22007-09-18 17:53
没人愿意帮跑一下吗?
#3
风月_无边2007-09-18 18:42

我這里還沒有配置好環境
#4
ziyi5552007-09-18 19:40

不知道你是怎么想的? 代码1 和代码2 都是Servlet吗?
是Servlet 为什么没有 init() 方法 没有 destory()方法..

RequestDispatcher rd = request.getRequestDispatcher("display"); //这里注意下

在你的 web.xml 中的 url-parttern 和 servlet-class 都检查一下

其他没有看出有问题
#5
netstriker2007-09-18 23:09
其实只要继承了HttpServlet就不用实现Servlet的接口了，因为HttpServlet已经实现了这一个Servlet的接口了，
其实楼主可能是ziyi555所说的 url-parttern 的映射出了问题。
#6
大嘴先生22007-09-20 13:04
以下是引用netstriker在2007-9-18 23:09:20的发言：
其实只要继承了HttpServlet就不用实现Servlet的接口了，因为HttpServlet已经实现了这一个Servlet的接口了，
其实楼主可能是ziyi555所说的 url-parttern 的映射出了问题。

应该是没什么问题
我注意url-patern了
#7
鼎愿远2007-09-20 15:57
method="post"  method="get"
#8
大嘴先生22007-09-24 19:51
<body>
<form Action="Login" method="post">//明明是post吗,怎么改get呢?
用户名:<input type="text" name="user">
密码: <input type="password" name="password">
<input type="submit">
</form>
</body>
#9
skyland842007-09-25 20:20
Action="Login" 和那两个 SEVERLRT 有什么关联了?

这样应该是提交到 LOGIN 的SEVERLET 吧~!
#10
大嘴先生22007-09-26 18:37

没什么关联
一个处理一个被
#11
千里冰封2007-09-27 14:50
以下是引用大嘴先生2在2007-9-18 11:11:11的发言：

import java.io.IOException;


import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;

public class SessionInfo1 extends javax.servlet.http.HttpServlet implements javax.servlet.Servlet {
static final long serialVersionUID = 1L;

public SessionInfo1() {
super();
}


protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html,charset=GBK");
String user = request.getParameter("uesr");//应该是user
HttpSession session = request.getSession();
if(user.length()>0)
{
session.setAttribute("user", user);
}
RequestDispatcher rd = request.getRequestDispatcher("display");
rd.forward(request, response);
}





protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doGet(request,response);
}
}
//代码2

import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
public class Display extends javax.servlet.http.HttpServlet implements javax.servlet.Servlet {
static final long serialVersionUID = 1L;
public Display() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("test/html;charset=GBK");
HttpSession session = request.getSession();
String user = (String)session.getAttribute("user");
if(user!=null)
{
response.getWriter().println("欢迎你"+user);
}
else
{
response.getWriter().println("请登陆");
}
}

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doGet(request,response);
}
}
//代码3
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=GBK">
<title>Login</title>
</head>
<body>
<form Action="Login" method="post">
用户名:<input type="text" name="user">
密码: <input type="password" name="password">
<input type="submit">
</form>
</body>
</html>

//帮忙看看,谢谢拉
#12
大嘴先生22007-09-27 18:26
老大就是老大
高!实在是高
谢谢拉
#13
风月_无边2007-09-27 18:34
不要犯這種錯誤﹗﹗
#14
大嘴先生22007-09-27 18:50
没办法
眼神不好
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