指针的应用问题 - 编程论坛

#2

HJin2007-09-18 10:59

int *t;

-->

int t;

#3

凌冰月2007-09-18 20:04

不可以呀！请高手再给看看呀！谢谢了！

#4

雨中飞燕2007-09-18 20:28

类型严重不匹配，指针与int怎么可以赋值？？？

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#5

Wartsola2007-09-18 21:20

…………这个……是C++?

建议楼主先去把C++ Primer看3至5遍。

[此贴子已经被作者于2007-9-18 21:26:09编辑过]

#6

xbw01142007-09-18 21:48

新手～不懂

#7

HJin2007-09-18 23:10

回复：（凌冰月）指针的应用问题

#include <iostream>
using namespace std;

int main()
{
int* a, * b;
int x, y, z;
int swap(int* m, int* n);
cin >> x;
cin >> y;
a = &x;
b = &y;
z = swap(a, b);
cout << * a << endl;
cout << * b << endl;

cout<<z<<endl;

return 0;
}

int swap(int* m, int* n)
{
int t;
t = * m;
*m = * n;
*n = t;
// cout<<*m;
// cout<<*n;
return (*m, * n); // returns value of *m. Is this what you want?
}

/**
Hi sister 凌冰月:

read more about passing by value and passing by reference/address.

Output:
5 6
6
5
5
Press any key to continue . . .
*/

#8

jinchaoren2007-09-19 13:09

C++是可以兼容C的.

#9

ackie2007-09-20 12:12

#include<iostream.h>
void swap(int *rx,int *ry);
int main()
{
int x,y;
cout<<"please enter two number:";
cin>>x;
cin>>y;
cout<<"before the swap...";
cout<<"x:"<<x<<"y:"<<y<<endl;
swap(x,y);
cout<<"after the swap...."
cout<<"x:"<<x<<"y:"<<y<<endl;
return 0;
}
void swap(int *rx,int *ry)
{
int temp;
temp=*rx;
*rx=*ry;
*ry=temp;
}

#10

jonc2007-11-02 17:28

#include<iostream.h>
void main()
{int *a,*b;
int x,y;
int swap(int *m,int* n);
cin>>x;
cin>>y;
a=&x;
b=&y;
swap(a,b);
cout<<*a;
cout<<*b;
}
int swap(int *m,int *n)
{
int t;
t=*m;
*m=*n;
*n=t;
// cout<<*m;
// cout<<*n;
return(*m,*n);
}