select sum(field/60) from tablename
有条件的,那样的话我还有问吗
create table #tbl1(feevalue int,minute int)create table #tbl2(feevalue int,minute money)
insert into #tbl1 select feevalue, feevalue / 60 from feeinsert into #tbl2 select feevalue, feevalue / 60 from fee
update #tbl1 set minute = a.minute + 1 from #tbl1 join #tbl2 on a.feevalue =b.feevalue and a.minute - b.minute <> 0 select sum(minute) from #tbl1