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求积分问题

包123 发布于 2007-06-21 10:35, 718 次点击
已知:
r(t)=A*cos(b*t)*exp(a*t)+B*sin(b*t)*exp(a*t) 0<t<=t1时
r(t1)-A*cos(b*(t-t1))*exp(a*(t-t1))+B*sin(b*(t-t1))*exp(a*(t-t1)) t>t1时

求:
r(t)的积分函数R(t)
其中:a b A B 都是常数量


[此贴子已经被作者于2007-6-21 10:42:03编辑过]

3 回复
#2
abingchem2007-06-21 21:49
int(A*cos(b*t)*exp(a*t)+B*sin(b*t)*exp(a*t),t)
#3
abingchem2007-06-22 08:18
rt1=subs(r,t,t1)-A*cos(b*(t-t1))*exp(a*(t-t1))+B*sin(b*(t-t1))*exp(a*(t-t1))

rt1 =

A*cos(b*t1)*exp(a*t1)+B*sin(b*t1)*exp(a*t1)-A*cos(b*(t-t1))*exp(a*(t-t1))+B*sin(b*(t-t1))*exp(a*(t-t1))

?int(rt1,t)

ans =

A*cos(b*t1)*exp(a*t1)*t+B*sin(b*t1)*exp(a*t1)*t-A*(a/(a^2+b^2)*exp(a*t-a*t1)*cos(-b*t+b*t1)-b/(a^2+b^2)*exp(a*t-a*t1)*sin(-b*t+b*t1))+B*(-b/(a^2+b^2)*exp(a*t-a*t1)*cos(-b*t+b*t1)-a/(a^2+b^2)*exp(a*t-a*t1)*sin(-b*t+b*t1))

?
#4
包1232007-06-22 10:04
谢谢
1