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关于枚举型问题

兜兜里有枪 发布于 2007-04-22 09:29, 460 次点击

#include <iostream>
using namespace std;

int main()
{
enum color
{red,yellow,blue,white,black};
enum collor pri;
int n,loop,i,j,k;
char c;
n=0;
for(i=red;i<=black;i++)
for(j=red;j<=black;j++)
if(i!=j)
{
for(k=red;k<=black;k++)
if((k!=i)&&(k!=j))
{
n=n+1;
cout.width(6);
cout<<n;

for(loop=1;loop<=3;loop++)
{
switch(loop)
{
case 1: pri=(enum color)i;break;
case 2: pri=(enum color)j;break;
case 3: pri=(enum color)k;break;
default: break;
}
switch(pri)
{
case red: cout<<"red";break;
case yellow: cout<<"yellow";break;
case blue: cout<<"blue";break;
case white: cout<<"white";break;
case black: cout<<"black";break;
default: break;
}
}
cout<<endl;
}
}
cout<<"total:"<<n<<endl;
}

错误在哪里啊?

2 回复
#2
wfpb2007-04-22 09:43
enum collor pri;
多写了个l
#3
yuyunliuhen2007-04-22 11:27
以下是引用兜兜里有枪在2007-4-22 9:29:55的发言:

#include <iostream>
using namespace std;

void main()
{
enum color
{red,yellow,blue,white,black};
// enum collor pri; // collor? 不小心拼写错了吧
enum color pri;
int n,loop,i,j,k;
// char c;
n=0;
for(i=red;i<=black;i++)
for(j=red;j<=black;j++)
if(i!=j)
{
for(k=red;k<=black;k++)
if((k!=i)&&(k!=j))
{
n=n+1;
cout.width(6);
cout<<n;

for(loop=1;loop<=3;loop++)
{
switch(loop)
{
case 1: pri=(enum color)i;break;
case 2: pri=(enum color)j;break;
case 3: pri=(enum color)k;break;
default: break;
}
switch(pri)
{
case red: cout<<"red";break;
case yellow: cout<<"yellow";break;
case blue: cout<<"blue";break;
case white: cout<<"white";break;
case black: cout<<"black";break;
default: break;
}
}
cout<<endl;
}
}
cout<<"total:"<<n<<endl;
}

错误在哪里啊?

1