十六进制的地址为什么要00开头而不是0x？ - 编程论坛

#2

一二三四五2007-01-25 19:11

不是十六进制,当然就不是0x开头了

#3

tyc6112007-01-25 23:15

你程序输出会00头？深表怀疑^_^

#4

醉生梦死2007-08-27 13:26

我试过,是以ox头的

#5

valentineyzq2007-08-29 22:43

我试过了，是以00开头的。我的机子上的16进制都是00开头。这是系统的差别吧？我觉得不碍事。

#6

天使梦魔2007-08-30 08:46

一样的，表示方法不同。
你多用用十六进制文本编辑器就知道了。
00就代表0*
如果要看整数型就用强制转换看看一不一样。
cout << "The value of a is " << a << " and the address of a is " << int(&a) << endl ;
cout << "The value of b is " << b << " and the address of b is " << int(&b) << endl ;

#7

HJin2007-08-30 09:28

#include <iostream>
using namespace std;
int main()
{
int a=10;
double b=10.11;

cout << "The value of a is " << a << " and the address of a is "<<hex<<showbase<< (int)(&a) << endl ;
cout << "The value of b is " << b << " and the address of b is " << &b << endl ;

return 0;
}

/** Output from VC 2005:

The value of a is 10 and the address of a is 0x12ff68
The value of b is 10.11 and the address of b is 0012FF6C
Press any key to continue . . .

Suggestion: if you want to show the base of a number, you may want to use
the io manipulators showbase or noshowbase, etc.

*/