[求助]如何从一个矩阵中取若干数组成新的几矩阵 - 编程论坛

#2

hitzhang2006-12-22 22:49

a=rand(4,4);
ab=a(1:2,3:4)%取1～2行3～4列付与ab

#3

wlyddd2006-12-23 12:47

再请教

A=[3 2 1 6 5 4; 9 8 7 1 2 3];

运行
a=rand(4,4);
ab=a(1:2,3:4)%取1～2行3～4列付与ab
结果:
ab =

0.8214 0.9218
0.4447 0.7382
不是得到分开的矩阵,如ab1和ab2，再请指教，谢谢，初学者。
另请教：矩阵的下标变量如何循环？谢谢！

#4

zhangenter2006-12-23 22:45

d = 3;
A=[3 2 1 6 5 4; 9 8 7 1 2 3] ;
[M,N] = size(A) ;
n = floor( N / d ) ;
for num1 = 1: M
for num2 = 1: n
B{num1, num2} = A(num1, num2:(num2+d-1)) ;
end
end

#5

wlyddd2006-12-24 11:09

谢谢4楼的指点,程序运行结果如下:
B =

[1x3 double] [1x3 double] [1x4 double] [1x4 double]
[1x3 double] [1x3 double] [] []

B =

[1x3 double] [1x3 double] [1x4 double] [1x4 double]
[1x3 double] [1x3 double] [] []

B =

[1x3 double] [1x3 double] [1x4 double] [1x4 double]
[1x3 double] [1x3 double] [] []

B =

[1x3 double] [1x3 double] [1x4 double] [1x4 double]
[1x3 double] [1x3 double] [] []
还是没有分开成几个新的矩阵.Workspace显示B为2×4 cell.到底生成几个或若干新矩阵该如何作?还请不吝多多赐教!

#6

zhangenter2006-12-24 16:57

已经分开了,B为2×4 cell,要提B的第m行,第n列矩阵用B{m,n}

#7

wlyddd2006-12-24 17:36

谢谢您,可能还是要写若干B1......Bn才行。