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代码:

package haha;

public class Untitled1 {
    public static void main(String[] args) {
        {
            int sum = 0;
            int n = 0;
            for (int i = 1; i <= 10; i++) {
                for (int j = i; j <= 10; j++) {
                    sum = i + j;
                    if (sum == 10) {
                        n++;
                    }
                  
                }

            }
            System.out.println("循环的次数" + n);
        }
    }
}
//我想实现相加=10的有几组

是连续相加的很简单   如果不是连续相加呢  

有9中情况

1+9  1+2+3+4  1+2+7   1+3+6  1+4+5

2+3+5  2+8

3+7   

4+6
5+5


  大家帮我看下！  谢谢了！！！！！！！！

[ 本帖最后由 hanzhu3366 于 2008-5-12 20:42 编辑 ]

你上面的程序叫单元加..你找看看啊

上面的程序多了一个大括号！

不是括号问题，第二个for循环有问题！  这个题目看似简单，还真有点小麻烦，希望大家帮我调试下！  

有10种，
1，2，7
1，3，6
1，4，5
2，3，5
1，2，3，4
其他5钟不说了

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代码:

public class Test {
    static int sum=0;
    static int count=0;
    public static void main(String[] args){
        
        int result=10;//相加后的结果
        
        //因为i=5,j=5在我这里是特殊的，因为他们相等而且相加刚好等于10,所以要特别给count+1,只要result%2==0都要加1
        if(result%2==0){
            count++;
        }
        
        for(int i=1;i<(result/2+1);i++){
            System.out.println("开始 i ="+i);
            for(int j=i+1;j<10;j++){
                System.out.println("开始 j ="+j);
                sum=i;
                sum+=j;
                if(i==1&&j==1){
                    continue;
                }
                if(sum>result){
                    break;
                }
                if(sum<result){
                    if((sum+j+1)<result){//表示三个或更多的数相加小于10
                        add(sum,j+1,result);
                    }else if (sum+j+1==result) {
                        count++;
                        System.out.println("count++:"+count);
                    }else{
                        continue;
                    }
                    System.out.println();
                }
                if(sum==result){
                    count++;
                    System.out.println("i:"+i+" &&& j:"+j+"   count="+count);
                    break;
                }
                
            }
        }
        System.out.println(count);
    }
    /**
     * @param i
     * @param j
     * @param result:相加后的结果
     */
    public static void add(int i,int j,int result){
        
        System.out.println("add中的i="+i);
        int temp=i;
        for(;j<result;j++){
            i=temp;
            i+=j;
            if(i<result){
                int temp1=i,temp2=j+1;
                System.out.println("temp1:"+temp1+" + temp2:"+temp2);
                if(temp1+temp2==result){
                    count++;
                    System.out.println("temp1:"+temp1+" + temp2:"+temp2+"   count="+count);
                }
                else if(temp1+temp2<result){
                    add(temp1, temp2,result);
                }
                
            }else if(i>result){
                break;
            }else if(i==result){
                count++;
                System.out.println("i:"+i+" + j:"+j+"   count="+count);
            }else{
                continue;
            }
        }
    }
}

谢谢你~~

6楼的不错!

复制内容到剪贴板

代码:

package wwwww;

public class Untitled1 {
    public static void main(String[] args) {
        int cnt2 = 10;

        for (int i = 1; i < 10; i++) {
            for (int j = 1; j < 10; j++) {
                if (i < j) {
                    if ((i + j) == cnt2) {
                        System.out.println("两个数相加的有： " + i + "+" + j);
                    }
                }
            }
        }

        for (int k = 1; k < 10; k++) {
            for (int n = 1; n < 10; n++) {
                for (int m = 1; m < 10; m++) {

                    if (k < n) {
                        if (n < m) {
                            if ((k + n + m) == cnt2) {
                                System.out.println("三个数相加的有： " + k + " " + n +
                                        " " + m);
                            }
                        }
                    }
                }
            }
        }

        for (int i = 1; i < 10; i++) {
            for (int j = 1; j < 10; j++) {
                for (int k = 1; k < 10; k++) {
                    for (int m = 1; m < 10; m++) {
                        if (i < j) {
                            if (j < k) {
                                if (k < m) {
                                    if ((i + j + k + m) == cnt2) {
                                        System.out.println("四个数字相加的有： " + i +
                                                " " + j + " " +
                                                k + " " + m);
                                    }
                                }
                            }
                        }
                    }
                }
            }
        }

    }

}

import java.io.*;
class demo{
private int k=0;
private int a[]=new int[100];
public  void num(int number)
{
int n1,j,temp=k,i;
for(j = 1 ; j <= number/2 + 1 ; j ++)
{
    if(number-j <= 0)  
        break;
    n1 = number - j;
    a[k ++] = j;
    if(n1 > 1)
        num(n1);
    else
    {
        a[k ++] = 1;
        System.out.println();
        for(i = 0 ; i < k-1 ; i ++)
            System.out.print(a[i]);
        System.out.print(a[k-1]);
    }
    k=temp;
}
System.out.printf("\n");;
for(i = 0 ; i < k ;i ++)
System.out.print(a[i]);
System.out.print(number);
}
public static void main(String []arg)
{
int m;
InputStreamReader isr=new InputStreamReader(System.in);
BufferedReader br=new BufferedReader(isr);
String s;
demo d=new demo();
try{
    s=br.readLine();
    m=Integer.parseInt(s);
    d.num(m);
}catch(Exception e)
{
    System.out.println(e.toString());
    }

}
}