#include <stdio.h>
#include <conio.h>
int main()
{
float apple_m=2.8;
float banana_m=1.7;
float manguo_m=6.5;
float apple=0.0;
float banana=0.0;
float manguo=0.0;
float pay,get,back;
int chose,screen=1;
char check2,check1=1;
while (screen)
{
clrscr();
printf("\n\n");
printf("\t\t\t*******************************\n");
printf("\t\t\t* How mouch momey *\n");
printf("\t\t\t* (1) Apple-----------2.8$ *\n");
printf("\t\t\t* (2) Banana----------1.7$ *\n");
printf("\t\t\t* (3) Manguo----------6.5$ *\n");
printf("\t\t\t* Other to done *\n");
printf("\t\t\t*******************************\n");
printf("\n");
printf("Witch do you want :");
scanf("%d",&chose);
switch (chose)
{
case 1:
printf("\nInput the weight: kg\b\b\b\b\b\b");
scanf("%f",&apple);
printf("\nOk,%.2fkg apples.\n",apple);
getchar();
break;
case 2:
printf("\nInput the weight: kg\b\b\b\b\b\b");
scanf("%f",&banana);
printf("\nOk,%.2fkg bananas.\n",banana);
getchar();
break;
case 3:
printf("\nInput the weight: kg\b\b\b\b\b\b");
scanf("%f",&manguo);
printf("\nOk,%.2fkg manguos.\n",manguo);
getchar();
break;
default :
screen=0;
}
printf("That's all?(y/n)\t");
scanf("%c",&check2);
if (check2=='y')
screen=0;
}
pay=apple*apple_m+banana*banana_m+manguo*manguo_m;
printf("\nOK!It's %.2f$\n",pay);
while (check1)
{
printf("\nGet : $\b\b\b\b\b");
scanf("%f",&get);
if (get<pay)
{
printf("It's not enaf");
}
else
check1=0;
}
back=get-pay;
printf("\nShuld back %.2f$",back);
getchar();
return 0;
}
/*问题1：在case语句中，比如在case1中，为什么我一旦取消了getchar()命令，
getchar()上面的语句printf("\nOk,%.2fkg apples.\n",apple);就无法执行？
或者说执行了却看不到效果？
问题2：为什么在case语句中的printf("\nOk,%.2fkg apples.\n",apple);第二
个“\n”命令没有效果？而ok前面的那个\n却有效果？*/
