求助!(页 1) - JAVA论坛 - J2SE论坛

xishuiwuqing 发表于 2008-4-3 08:20

求助!

在JAVA中,给定一个正整数 m ,判断它的具体位数,分别打印没一位数,再按照逆序打印出各位数.
例如这里的 m=24863.这个程序怎么写啊???

xishuiwuqing 发表于 2008-4-3 08:41

急啊

怎么还没反映呢?

freish 发表于 2008-4-3 08:59

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.text.AttributeSet;
import javax.swing.text.BadLocationException;
import javax.swing.text.PlainDocument;

public class NumAna extends JFrame{
private Container container;
private JTextField input;
private JTextArea output;
private JLabel inputLabel;
private JButton button,closeButton;

public NumAna(){
super("数字判断");

container = getContentPane();

input = new JTextField("",15);
inputLabel = new JLabel("请输入数字");
input.setDocument(new customDoc());
output = new JTextArea(20,30);
output.setEditable(false);

button = new JButton("分析");
button.addActionListener(
new ActionListener(){
public void actionPerformed(ActionEvent event){
String num = input.getText();
if(num.length()==0)
output.setText("您没有输入数字。");
else{
output.append("您输入的是："+input.getText()+"，是"+num.length()+"位数.\n");
for(int i=0;i<num.length();i++)
output.append("第"+(i+1)+"位数是："+num.charAt(i)+"\n");
output.append("\n");
StringBuffer buf = new StringBuffer(num);
buf.reverse();
output.append("逆序后为"+buf.toString()+"\n");
input.setText("");
for(int i = 0;i<buf.toString().length();i++)
output.append("第"+(i+1)+"位数是："+buf.toString().charAt(i)+"\n");
}
input.grabFocus();
}
}
);
closeButton = new JButton("关闭");
closeButton.addActionListener(
new ActionListener(){
public void actionPerformed(ActionEvent event){
System.exit(0);
}
}
);
JPanel panel1 = new JPanel();
panel1.setLayout(new FlowLayout());
panel1.add(inputLabel);
panel1.add(input);
container.add(new JScrollPane(output));
JPanel panel2 = new JPanel();
panel2.setLayout(new FlowLayout());
panel2.add(closeButton);
panel2.add(button);
container.add(panel1,BorderLayout.NORTH);
container.add(panel2,BorderLayout.SOUTH);

pack();
Toolkit kit = Toolkit.getDefaultToolkit();
Dimension screenSize = kit.getScreenSize();
int screenHeight = screenSize.height;
int screenWidth = screenSize.width;
setLocation((screenWidth - 800) / 2, (screenHeight - 110) / 2);

setVisible(true);
setResizable(false);
}

public static void main(String args[]){
NumAna num = new NumAna();
num.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}
}

class customDoc extends PlainDocument{
public void insertString(int offs, String str, AttributeSet a)
throws BadLocationException {
for(int i=0;i<str.length();i++){
if(str.charAt(i)<'0'||str.charAt(i)>'9'){
return;
}
}
super.insertString(offs,str,a);

   }
   }

[[it] 本帖最后由 freish 于 2008-4-3 09:03 编辑 [/it]]

freish 发表于 2008-4-3 09:00

转换成String就是很好搞的一个东西

xishuiwuqing 发表于 2008-4-3 10:04

回复 3# 的帖子

谢谢!
我也做好了,呵呵 !
package lk3;

public class lk {
public static void main(String[] args) {
      int m = 24689, i, j, k, n = 1, w;
      w = m;
      // if(m>=0&&m<10){
      //    System.out.println("m是一位数");
      // }
      // if(m>=10&&m<100){
      //    System.out.println("m是二位数");
      // }
      // if(m>=100&&m<1000){
      //    System.out.println("m是三位数");
      // }
      // if(m>=1000&&m<10000){
      //    System.out.println("m是四位数");
      // }
      // if(m>=10000&&m<100000){
      //    System.out.println("m是五位数");
      // }

      for(j=1;;j++){

      if (w / 10 != 0) {
         n++;
         w = w / 10;
      } else {
         break;
      }
      }
      System.out.println("m的位数是:" + " " + n);

      for (i = 1; i <= 5; i++) {
         k = m % 10;
         m = m / 10;
         System.out.println(" " + k);
      }
   }
}

tomhuatek 发表于 2008-4-5 05:46

哈哈

class Test{
public static void main(String[] args){

int m = 24863;
      String s = Integer.toString(m);
      byte[] bb = new byte[5];
      bb = s.getBytes();
      for(int i = 0; i < 5; i++){
        System.out.println(bb[i] - 48);
      }

}
}

这样是不是很简单啊

xishuiwuqing 发表于 2008-4-24 10:05

回复 6# 的帖子

呵呵,谢谢 !
的确更简单了!

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