用这个能求e的x次幂吗?
<P>#include<stdio.h><BR>#include<math.h><BR>void main()<BR>{[em13]<BR> <BR> int j,n,x;</P><P> float sum=0.0;<BR> int term=1;<BR> n=32;<BR> printf("请输入x\n");<BR> scanf("%d",&x);<BR> for(j=0;j<=n;++j)<BR> {<BR> term=term*x/j;<BR> sum=sum+term;<BR> if(term<=1e-8)<BR> break;<BR> }<BR> printf("e的x次幂=%f\n",sum);<BR>}</P>
<P>那怎么求e的x次幂</P> exp()
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